Selection guide

Peak power, pulse width and duty cycle: the three numbers that define a pulsed laser diode

Peak power sells the part, pulse width sets the resolution, and duty cycle decides whether it survives. Getting the relationship wrong is the most common way a pulsed laser design fails.

Updated 2026-10-07 · 4 min read


The relationship

Three numbers, one identity:

E [µJ] = Ppeak [W] × tp [ns] × 10-3
Pavg = Ppeak × D    where D = tp × frep is the duty cycle

Everything else follows. Pulse energy sets reach. Duty cycle sets heat. Pulse width sets resolution.

Peak power is a marketing number

A 180 W diode and a 90 W diode at the same 100 ns are very different; a 180 W diode at 50 ns and a 90 W diode at 100 ns are the same system - both deliver 9 uJ. Peak power alone tells you nothing about range.

This matters commercially, because datasheets lead with peak power. When you compare parts, convert to energy first. Our own catalogue does this: every pulsed laser diode page lists pulse energy at 100 ns next to the peak power figure.

Pulse width: resolution, blind zone, and driver cost

Range resolution is set by pulse width:

ΔR = c · tp / 2

For tp = 100 ns, ΔR = 15 m. For 10 ns, 1.5 m. For 1 ns, 15 cm.

The same number sets the receiver bandwidth you need (BW ≈ 0.4 / tp), which sets your noise floor. It also sets the blind zone - a receiver cannot see a return until its own pulse has finished, so a 100 ns pulse cannot measure anything closer than about 15 m without special techniques.

Consequences:

Pulse widthResolutionReceiver BWTypical application
1 - 5 ns15 - 75 cm80 - 400 MHzSurveying, high-precision metrology
10 ns1.5 m40 MHzAutomotive LiDAR, robot navigation
50 ns7.5 m8 MHzIndustrial proximity, gesture
100 ns15 m4 MHzHandheld rangefinders, drones

Note the trade: a narrower pulse gives you resolution and a worse noise floor. At 1 ns you are integrating 100x more noise bandwidth than at 100 ns, which costs roughly 10 dB of sensitivity. That is why the range equation holds energy, not peak power, as the figure of merit: a 1 ns pulse at 100 W gives you the same reach as a 100 ns pulse at 1 W, at 100x the driver difficulty.

Duty cycle: the number that decides survival

The catastrophic failure mode in pulsed laser diodes is not peak power - it is average power. A TO56 can with a 110 x 30 µm emitting area can dissipate a few hundred milliwatts of heat. Push it further and the facet coating degrades, threshold current climbs, and the part dies in tens of hours instead of tens of thousands.

Worked example with PLD905-180W-M:

D = tp × f = 100 ns × 3 kHz = 0.03 %
Pavg = 180 W × 0.0003 = 54 mW

Comfortable. The datasheet allows up to 0.1 %, which at 3 kHz means you could stretch the pulse to 300 ns - but then you would be running 54 mW of average power and a longer pulse. Most designs sit well inside the rating and treat the remaining duty cycle headroom as thermal margin.

What breaks designs:

Forgetting that duty cycle scales with both variables. Doubling the repetition rate and keeping the pulse width doubles the average power.

Ignoring wavelength drift with temperature. At 0.28 nm/K, a 40 K rise moves the peak wavelength 11 nm - enough to walk off the edge of a 10 nm bandpass filter and silently lose half your signal. Low-drift parts like PLD905AL-70W-M hold 0.10 nm/K specifically for this reason.

Assuming the receiver filter is wide enough. It usually is not. Match the filter passband to the diode's temperature-widened spectrum, not to its 25 °C value.

Practical selection rules

Start from energy, not power. Decide the range you need, convert through the range equation, then choose a pulse width from the resolution requirement, and only then read off the peak power you need.

Pick the longest pulse your resolution allows. It is easier to drive, needs less receiver bandwidth, has a better noise floor, and puts less stress on the driver electronics.

Keep average power at half the rated duty cycle. It buys thermal margin for high-temperature operation and for the wavelength drift that comes with it.

Check the emitter count and aperture. The same 75 W is available as three 200 x 10 µm emitters or four 90 x 18 µm emitters. The first gives you a wide, thin line; the second a more compact spot. That choice interacts with your collimation optics - see beam shaping.


Related reading

Have a specification, not a part number?

Send us the requirement - range, target, size, budget - and an engineer will come back with parts and the trade-offs between them.

Ask an engineer